WebbNew York. Problem 32. Q. A merry-go-round accelerates from rest to 0.68 \textrm { rad/s} 0.68 rad/s in 34 s. Assuming the merry-go-round is a uniform disk of radius 7.0 m and mass 31,000 kg, calculate the net torque required to accelerate it. A. 1.5 \times 10^4 \textrm { N m} 1.5× 104 N m. Webb31 mars 2024 · With the merry-go-round rotating at constant angular velocity, for an object fixed at the edge of the merry-go-round, in the inertial frame (observer on the ground) the object is accelerating due to the change in its velocity vector even though its speed is constant (acceleration is a vector).

angular momentum - Why does jumping off a merry go round in the radial

Webb12 dec. 2011 · "A merry-go-round is spinning with a fixed angular speed. As a person is walking towards the edge, the force of static friction must increase in order for the … flory septic

Relative Motion – Merry-go-round problem

WebbIt is spinning about a frictionless axle through its center, but at one point on its equator it is scraping against metal, resulting in a friction force of 0.0200 N at that point. (a) Find its angular acceleration. A playground merry-go-round has radius 2.40 m and moment of inertia 2100 kg•m^2 about a vertical axle through its center, and it ... Webb10 dec. 2013 · Visit http://ilectureonline.com for more math and science lectures!In this video I will show you how to find angular velocity(final)=? (relative to the groun... Webb16 aug. 2024 · $\begingroup$ It's worth noting that the "jump force" $\vec{J}$ will in fact exert a torque on the merry-go-round, due to its upward component. But this torque would tend to twist the disc around … florysem